(b) Find out the current through the cell and voltage across it from the given circuit diagram.

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Physics
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babykins
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1 year ago

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Answer:

answer will be 60 Amphere for sire

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keltonhk4t
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Answer:

The current through the cell and voltage across it is 4 A and 2 volts respectively.

Explanation:

The current and voltage across the cell will be calculated through the ohms law. Which is given as,

[tex]V=IR[/tex] (1)

Where,

V=potential difference

I=current through the circuit

R=resistance of the circuit

From the question we have,

R₁=3Ω

R₂=2Ω

R₃=10Ω

R₄=10Ω

The internal resistance of the cell(r)=0.5

The potential difference of the circuit(V)=12volt

The resistors R₁ and R₂ are connected in series. So, their net resistance will be,

[tex]R_s=R_1+R_2[/tex]

[tex]R_s=2+3=5\Omega[/tex] (2)

Now the resistors R₃, R₄ and [tex]R_s[/tex] are connected in parallel. So,

[tex]\frac{1}{R_p}=\frac{1}{R_3} +\frac{1}{R_4} +\frac{1}{R_s}[/tex] (3)

By substituting all the required values in equation (3) we get;

[tex]\frac{1}{R_p}=\frac{1}{10} +\frac{1}{10} +\frac{1}{5}[/tex]

[tex]\frac{1}{R_p}=\frac{1+1+2}{10}[/tex]

[tex]R_p=\frac{10}{4}[/tex]

[tex]R_p=2.5\Omega[/tex] (3)

The net resistance of the circuit is,

[tex]R=R_p+r[/tex] (4)

By substituting the values in equation (4) we get;

[tex]R=2.5+0.5[/tex]

[tex]R=3\Omega[/tex] (5)

By using equation (1) the current through the cell is calculated as,

[tex]12=I\times 3[/tex]

[tex]I=\frac{12}{3}[/tex]

[tex]I=4A[/tex] (6)

The voltage across the cell(e) will also be calculated using equation (1) which is given as,

[tex]e=I\times r[/tex] (7)

By placing the values in equation (7) we get;

[tex]e=4\times 0.5[/tex]

[tex]e=2Volt[/tex]

Hence, the current through the cell and voltage across it is 4 A and 2 volt respectively.

#SPJ3

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brown sugar3zj7
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(b) Find out the current through the cell and voltage across it from the given circuit diagram.

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