a projectile is launched with velocity of 20i+30j m/s takeing horizot as x axis and vertical upward as positive y axis with what velocity it will teach the level of projection​

Step-by-step explanation:

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( 10p + 16q ) + ( 15p + 12q ) = 25p + 28q

Given :

The expressions 10p + 16q and 15p + 12q

To find :

Add the expressions

Solution :

Step 1 of 2 :

Write down the given expressions

The given expressions are

10p + 16q and 15p + 12q

Step 2 of 2 :

Add the expressions

[tex] \sf ( 10p + 16q ) + ( 15p + 12q )[/tex]

[tex] \sf = 10p + 16q + 15p + 12q [/tex]

[tex] \sf = (10 + 15)p + (16 + 12)q [/tex]

[tex] \sf = 25p + 28q [/tex]

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Step-by-step explanation:

class                  f                    cf   

0-10                  10                  10

10-20                x                   10+x

20-30              25                  35+x

30-40              30                  65+x

40-50               y                   65+x+y

50-60              10                  75+x+y      

                75+x+y    

 75+x+y=100

         x+y=25

f=30,h=10,cf=35+x,2n=50

      Median=l+(f2n−cf)×h    

             32=(3050−35−x)×10              

            32−30=315−x   

            6=15−x

            x=9

              ∴y=16

Explanation:

जुदा=न्यारा,अलहदा, विलग, पृथक, अलग-थलग।

Step-by-step explanation:

C.

2

Correct Answer

D.

SOLUTION

The correct option is C.

Given,

A friction less wire AB. And a sphere of radius R.

Acceleration of body along

Distance traveled in time is:

Now,

From

Concept introduction:

Missing numbers are those that have been omitted from a particular set of numbers that have comparable discrepancies between them.

Explanation:

Given that, E5,?,O6,T2,Y7

We have to find, the missing code in the sequence.

According to the question,

The letters are progressing in the pattern of +[tex]5[/tex] of their numeric value, and the numbers are progressing in pattern - [tex]4[/tex], +[tex]5[/tex], - [tex]4[/tex], +[tex]5[/tex].......

Hence the missing letter is E= [tex]5[/tex] ; [tex]5 + 5[/tex] = [tex]10[/tex] ⇒ J

And missing number is [tex]5 - 4[/tex] [tex]= 1[/tex]

Final Answer:

The missing of in this sequence is J[tex]1[/tex].

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