A projectile is launched with initial velocity Vo= (2î + 3j) m's. The equation of trajectory of particle is (g = 10 m/s) a) y = 4x - 6x ^2b) 4y = 6x - 5x^2c) 4y = 3x - 10x^2 d)y = 4x - 5x^2​

Answer:

pi orbital

Explanation:

bec there is weak pi bond that's why comparative sigma bond

Explanation:

• [tex]B2+[/tex]  has 10 electrons  

• Its electronic configuration is [tex]sigma (1s), 2 sigma*(1s) ,2 sigma(2s), 2 sigma* (2s) ,2 pi (2p) x1, Pi 2p y1[/tex]

• Here unpaired electrons are found and due to the presence of unpaired electrons, the nature is paramagnetic.

• Here the highest occupied molecular orbital is of [tex]\pi[/tex] orbital.
• pi bonds are covalent chemical bonds.
• They can form a double and triple bonds but do not form single bonds.
• They involve complete overlapping of two lobes of atomic orbital with the other.

Answer:

cotton is exposed to the air or black carbon it turns into black

• The fine cotton thread-like structure is a member of kingdom fungi and its name is Rhizopus stolonifer.
• The branching fine cotton thread is called hyphae and all the hyphae are together known as mycelium.
• The bread mould forms spores inside a sporangium. When it breaks open, they germinate to form a new mould.
• The new mould appears black in colour.

Answer:

Hence, this electrons goes to antibonding π molecular orbital.

During the change of N2 to N2-, the added electron goes to (π*2px) molecular orbital.

In N2- we have 15 electrons and there are 10 bonding electrons and 5 anti-bonding electrons. In N2- we have one unpaired electron so it also shows some magnetic moment.

The bond order of N2- is 2.5 while the bond order for N2 is 3. As bond order is inversely proportional to bond strength the bonds formed by N2- will be weaker as compared to N2. the bond length of N2- will be more.

Answer:

here is your answer hope it helps

• Assuming the situation as a right angled triangle.
• His speed when he runs = 6 m/s ([tex]v_{m}[/tex]) in x-axis
• Angle of incline = 37 degrees w.r.t to the vertical
• Let the speed of rain be v[tex]_{r}[/tex] but w.r.t to man the speed of rain is v[tex]_{m}[/tex] (x axis) -v(y axis)

         tan 37° = [tex]\frac{6}{v}[/tex]

             [tex]\frac{3}{4} =\frac{6}{v} \\v= 8[/tex]

Therfore speed of rain = 6i - 8j

Total numerical value of speed of rain is [tex]\sqrt{6^{2}+8^{2}\\[/tex]

                                                                   [tex]\sqrt{36+64}[/tex]

                                                                  = 10 m/s