Step-by-step explanation:
Radius of circular loop 1 = 6.28cm
Radius of circular loop 2 = 3.14cm
The current passing through each of them = 2A
Value of μ = 4 x 10-7 Wb/ A.m
To Find:
The value of the magnetic field at their common center.
Solution:
The value of the magnetic field due to the circular coil,
B = μ₁ x
The value of the magnetic field of loop 1 (B1)= Ho 26.28=2×10 7 Wb/m²
Similarly. The value of B₂ = 4x10-7 Wb/m²
Both the magnetic fields are right angles to each other.
So, the net magnetic field (B) = √(B1²+ B22) = 2√5 x 10-7 Wb/m²
Hence, the magnitude of the net magnetic field at their common center is 2√5×10 7 Wb/m².
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