Two circular loops of radii 6.28 cm and 3.14 cm are arranged concentric to one another with their planes at right angles to each other. if a current of 2 a is passed through each of them, calculate the magnitude of the magnetic field at their common centre (given: ).

  • matematika

    Subject:

    Math
  • Author:

    renee
  • Created:

    1 year ago

Answers 1

Step-by-step explanation:

Radius of circular loop 1 = 6.28cm

Radius of circular loop 2 = 3.14cm

The current passing through each of them = 2A

Value of μ = 4 x 10-7 Wb/ A.m

To Find:

The value of the magnetic field at their common center.

Solution:

The value of the magnetic field due to the circular coil,

B = μ₁ x

The value of the magnetic field of loop 1 (B1)= Ho 26.28=2×10 7 Wb/m²

Similarly. The value of B₂ = 4x10-7 Wb/m²

Both the magnetic fields are right angles to each other.

So, the net magnetic field (B) = √(B1²+ B22) = 2√5 x 10-7 Wb/m²

Hence, the magnitude of the net magnetic field at their common center is 2√5×10 7 Wb/m².

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