A freight train left San Diego and travelled east at an average speed of 28mph. A diesel train left one hour later and travelled in the same direction but with an average speed of 33mph. Find the number of hours the freight train travelled before the diesel train caught up.Don't Spam

Subject:
Math
Author:
grizzly54
Created:
1 year ago

Answers 2

[tex]\large{\bf{ Given-}}[/tex]

A freight train left San Diego and travelled east at an average speed of 28mph.

A diesel train left one hour later and travelled in the same direction but with an average speed of 33mph.

[tex]\large{\bf{ To \: Find-}}[/tex]

Find the number of hours the freight train travelled before the diesel train caught up.

[tex]\large{\bf{Solution -}}[/tex]

Given that a freight train travelled east at an average speed of 28mph. A diesel train left one hour later and travel in the east direction but with an average speed of 33 mph.

of 33 mph.As the diesel train left after 1 hour so it is clear that the freight train had travelled 28m.

travelled 28m.Also, the difference between the speed of the train is 33mph - 28mph = 5mph.

travelled 28m.Also, the difference between the speed of the train is 33mph - 28mph = 5mph.Therefore the diesel train will reach 5m nearer to the freight train in the interval of every 1 hrs.

travelled 28m.Also, the difference between the speed of the train is 33mph - 28mph = 5mph.Therefore the diesel train will reach 5m nearer to the freight train in the interval of every 1 hrs.Therefore the train will gets close to it in 28/5 = 5.6 hrs or 5 hrs 36 min.

Author:

honoriomdtn
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10

Answer:

Notice that when the diesel train started, the freight train was 55 miles ahead.

But the diesel train, having the speed in 5 = 60-55 miles per hour greater than the freight train,

will decrease the distance between them by 5 miles each hour.

So, it will take 11 hours ( where 11+=+55%2F5 ) for the diesel train to catch the freight train.

Correspondingly, it will take 12 = 11+1 hours for the freight train to get the meeting point.

It is how the physicists solve such problem.

Below find the way on how this problem is solved in Algebra.

Let t = "How long did the freight train travel before the diesel train caught up", in hours (the value under the question).

Then the diesel train traveled (t-1) hour.

They both covered the same distance:

60*(t-1) = 55*t

60t - 60 = 55t

60t - 55t = 60 ====> t = 60%2F5 = 12 hours.

Step-by-step explanation:

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cookiefowler
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A freight train left San Diego and travelled east at an average speed of 28mph. A diesel train left one hour later and travelled in the same direction but with an average speed of 33mph. Find the number of hours the freight train travelled before the diesel train caught up.Don't Spam​

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A freight train left San Diego and travelled east at an average speed of 28mph. A diesel train left one hour later and travelled in the same direction but with an average speed of 33mph. Find the number of hours the freight train travelled before the diesel train caught up.Don't Spam