3) The arithmetic mean of 2, 4, 6, 8, 10 is ?​

Answer:

2520

Step-by-step explanation:

2520 is the smallest number that can be divided by each of the numbers from 1 to 10 without any remainder. What is the smallest positive number that is evenly divisible by all of the numbers from 1 to 20?

To find: The smallest number that can be divided by each of the numbers from 1 to 20 without any remainder.

• We just need to take L.C.M. the smallest number that can be divided by each of the numbers from 1 to 20 without any remainder.

• The Least Common Multiple (LCM) is also referred to as the Lowest Common Multiple (LCM) and Least Common Divisor (LCD). For two integers a and b, denoted LCM(a,b), the LCM is the smallest positive integer that is evenly divisible by both a and b. For example, LCM (2,3) = 6 and LCM (6,10) = 30.

• The LCM of two or more numbers is the smallest number that is evenly divisible by all numbers in the set.

Let's do this in listing factors method.

Write down factoriaztion of each number:

1 = 1

2 = 2

3 = 3

4 = 2 * 2

5 = 5

6 = 2 * 3

7 = 7

8 = 2 * 2 * 2

9 = 3 * 3

10 = 2 * 5

11 = 11

12 = 3 * 2 * 2

13 = 13

14 = 2 * 7

15 = 3 * 5

16 = 2 * 2 * 2 * 2

17 = 17

18 = 2 * 3 * 3

19 = 19

20 = 2 * 2 * 5

Write the primes vertically. (As in attachment 1)

Bring down numbers in each column and multiply to get LCM. (As in attachment 2)

Answer:

MyQuestionIcon

Question

If the original size of an image is

540

×

680

, which of the following image sizes cannot be achieved to ensure there is no deformation in the picture?

A

135 times 170

B

27 times 34

C

1080 times 1360

D

123 times 164

Solution

The correct option is D

123 times 164

To solve this question, we need to check how

540

×

680

can be reduced or expressed as higher fractions without changing the value of this ratio. To do this, recall that ratios are mathematically, just fractions. So, let us jump into fractions.

Dividing the numerator and denominator of the original fraction with the same number won't change the value of the fraction. Dividing with

4

, we get,

(

540

÷

4

)

/

(

680

÷

4

)

=

135

/

170

.

Similarly, dividing this fraction with

5

(on numerator and denominator) would result in

27

/

34

.

Our original fraction is

540

/

680

. Multiplying the numerator and the denominator of the fraction with a same number would not change the value of this fraction. Multiplying with

2

, we get,

(

540

×

2

)

/

(

680

×

2

)

=

1080

/

1360

Going in a similar way, we observe that the original fraction cannot be written as

123

/

164

and hence this picture size cannot be achieved without compromising the picture quality.

Step-by-step explanation:

brainlist

Explanation:

initial velocity of particle, u = 10j m/s

acceleration of particle , a = (8i + 2j) m/s²

displacement of particle in x direction , x = 16m

(a) so, use formula x=u_xt+\frac{1}{2}a_xt^2x=u

x

t+

2

1

a

x

t

2

here, u_x=0,a_x=8m/s^2u

x

=0,a

x

=8m/s

2

so, 16 = 0 + 1/2 × 8 × t²

or, 16 = 4t² => t = 2

hence, after 2 sec particle moves 16m in x direction.

now we have to find y - co-ordinate of particle at 2 sec.

so, use formula, y=u_yt+\frac{1}{2}a_yt^2y=u

y

t+

2

1

a

y

t

2

here, u_y=10m/s^2u

y

=10m/s

2

, a_y=2m/s^2a

y

=2m/s

2

, t = 2sec

so, y = 10 × 2 + 1/2 × 2 × 2²

y = 20 + 4 = 24m

(b) velocity of particle in x direction after 2 sec, v_x=u_x+a_xtv

x

=u

x

+a

x

t

= 0 + 8i × 2 = 16i m/s

velocity of particle in y direction after 2 sec ,

v_y=u_y+a_ytv

y

=u

y

+a

y

t

= 10 j + 2j × 2= 14j m/s

hence, speed , |v| = \sqrt{v_x^2+v_y^2}

v

x

2

+v

y

2

= \sqrt{16^2+14^2}

16

2

+14

2

= 21.26m/s

Answer:

The percentage value for 16/5 is 320%.

Step-by-step explanation:

Step-by-step explanation:

16 /5

=> 16 / 5 X 100

=16 X 20 =320%