Which smallest number can be divisible by numbers from 1 to 20 ?
Answers 2
Answer:
2520
Step-by-step explanation:
2520 is the smallest number that can be divided by each of the numbers from 1 to 10 without any remainder. What is the smallest positive number that is evenly divisible by all of the numbers from 1 to 20?
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Author:
lorenavaldez
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Rate an answer:
10
To find: The smallest number that can be divided by each of the numbers from 1 to 20 without any remainder.
- We just need to take L.C.M. the smallest number that can be divided by each of the numbers from 1 to 20 without any remainder.
Note:
- The Least Common Multiple (LCM) is also referred to as the Lowest Common Multiple (LCM) and Least Common Divisor (LCD). For two integers a and b, denoted LCM(a,b), the LCM is the smallest positive integer that is evenly divisible by both a and b. For example, LCM (2,3) = 6 and LCM (6,10) = 30.
- The LCM of two or more numbers is the smallest number that is evenly divisible by all numbers in the set.
Let's do this in listing factors method.
Step 1: BelowWrite down factoriaztion of each number:
1 = 1
2 = 2
3 = 3
4 = 2 * 2
5 = 5
6 = 2 * 3
7 = 7
8 = 2 * 2 * 2
9 = 3 * 3
10 = 2 * 5
11 = 11
12 = 3 * 2 * 2
13 = 13
14 = 2 * 7
15 = 3 * 5
16 = 2 * 2 * 2 * 2
17 = 17
18 = 2 * 3 * 3
19 = 19
20 = 2 * 2 * 5
Step 2: (As in attachment 1)
Write the primes vertically. (As in attachment 1)
Step 3: As in attachment 2)Bring down numbers in each column and multiply to get LCM. (As in attachment 2)
We get Answer as LCM (1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20) = 232792560Please mark me as Brainlist!Thank you :)
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Author:
cadencekibs
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Rate an answer:
4