If the enthalpy of hydrogenation of C6H6(l) into C6H12(l) is - 205 kJ and the resonance energy 0nly G's XECYNZ POBR of C6H6(l) is -152 kJ/mol then the enthalpy of hydrogenation of cyclohexene is: (Assume ΔHvap of C6H6(l), C6H8(l), C6H12(l) all are equal). a.−535.5 kJ/mol b.−238 kJ/mol c.−357 kJ/mol d.−119 kJ/mol​

Answers 1

Answer:Correct option is D)

Total enthalpy of hydrogenation if resonance doesn't happen =−205+(−152)=−357 kJ/mol

So for given molecule (single double bond) energy of hydrogenation is −357/3=−119 kJ/mol

Explanation:

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    cora

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