Answer:
The correct answer are 21.11m/s, 14420m and 8.01m/s.
Explanation:
Given:
S = 22+12+14
= 38Km
= 38000m
T = 1800s
Here,
The total distance is denoted by X.
The time is denoted by T.
The displacement is denoted by D.
The average velocity is denoted by V.
The average speed is denoted by S.
Now,
For part A,
By the equation,
\begin{gathered}S=\frac{X}{T} \\S=\frac{38000}{1800}\\S= 21.11m/s\end{gathered}
S=
T
X
S=
1800
38000
S=21.11m/s
So, the average speed is 21.11m/s.
Then,
For part B,
D = \sqrt{(22-14)^{2}+ 12^{2} }
(22−14)
2
+12
2
= 14.42Km
= 14420m
So, the sisplacement is 14420m.
Then,
For part C,
By the equation,
\begin{gathered}V=\frac{D}{T} \\V=\frac{14420}{1800}\\V= 8.01m/s\end{gathered}
V=
T
D
V=
1800
14420
V=8.01m/s
So, the average velocity is 8.01m/s.
Step-by-step explanation:
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