External radius of a 5m long hollow copper tube is 1.4 cm and it's thickness is 3.5mm. If resistivity of copper be 1.62, then find the resistance of the tube.
R= Resistance of the wirep= specific resistancel=length of the wirea= area of cross section of the wireWith the given values,A= 1.96349541*10^-7p = 1.6*10^-8R= 10l=(10*1.96349541*10^-7) /(1.6*10^-8)l=122.7m
