Answer:
2pix/y
Explanation:
We know-
Magnitude of maximum velocity of a body executing SHM = AW --(1)
Magnitude of maximum acceleration of a body executing SHM = AW^2--(2)
Here, A- Amplitude of SHM, and W- angular frequency of SHM
Both the above values have been derived from the equations of velocity and acceleration for an standard SHM. Just substitute 1 in place of Sin/ Cos function to get maximum value.
Now, going back to the question,
Divide (1) by (2)
We get--> 1/W=x/y
Hence, W=y/x
But W=2pi/T (Where T- time period of SHM)
Hence, 2pi/T=y/x
After rearranging, we get - T=2pix/y