on the outline map of India Mark and label the following rivers Ganga Satluj Damodar Krishna Narmada Tapi Mahanadi and BrahmaputraDON'T SPAM !​

Explanation:

Gandhiji choose to break the salt law because in his view, it was sinful to tax salt since it is such as essential item of our food that is used by the rich or the poor person in the same quantity.

Answer:

Gandhiji choose to break the salt law because in his view, it was sinful to tax salt since it is such as essential item of our food that is used by the rich or the poor person in the same quantity.

Given,

The number: 20.22

To find,

The value of the number in fraction form.

Solution,

The value of 20.22 in the fraction form will be [tex] \frac{1011}{50} [/tex].

According to the question,

The number: 20.22

Removing the decimal point:

[tex] \frac{2022}{100} [/tex]

(Note that when we are moving the decimal point to the right then the same number of zeroes with 1 are written in the denominator.)

We can convert this fraction into the simplest form by dividing it by 2:

[tex] \frac{1011}{50} [/tex]

Hence, the value of 20.22 in the fraction form is [tex] \frac{1011}{50} [/tex].

Answer:

final answer is x⁴-1

Step-by-step explanation:

step1: (x-1)^8-4

step2: (x-1)^4

step3: x^4-1^4

step4: x⁴-1

Given to evaluate:

[tex] \tt = \dfrac{d}{dx} \bigg( \dfrac{ {x}^{8} - 1}{ {x}^{4} - 1} \bigg)[/tex]

Can be written as:

[tex] \tt = \dfrac{d}{dx}\dfrac{({x}^{4})^{2} - {(1)}^{2} }{ {x}^{4} - 1}[/tex]

[tex] \tt = \dfrac{d}{dx}\dfrac{({x}^{4} + 1)( {x}^{4} - 1)}{ {x}^{4} - 1}[/tex]

[tex] \tt = \dfrac{d}{dx}({x}^{4} + 1)[/tex]

We know that:

[tex] \tt \longrightarrow \dfrac{d}{dx}(f \pm g) = \dfrac{df}{dx} \pm \dfrac{dg}{dx} [/tex]

Using this result, we get:

[tex] \tt = \dfrac{d}{dx}({x}^{4})+ \dfrac{d}{dx}(1)[/tex]

We know that:

[tex] \tt \longrightarrow \dfrac{d}{dx}( {x}^{n} ) =n {x}^{n - 1} [/tex]

[tex] \tt \longrightarrow \dfrac{d}{dx}(k) =0[/tex]

Using this result, we get:

[tex] \tt = 4{x}^{3} + 0[/tex]

[tex] \tt = 4{x}^{3} [/tex]

Therefore:

[tex] \tt \longrightarrow\dfrac{d}{dx} \bigg( \dfrac{ {x}^{8} - 1}{ {x}^{4} - 1} \bigg) =4 {x}^{3} [/tex]

Which is our required answer.

[tex]\begin{gathered}\boxed{\begin{array}{c|c}\bf f(x)&\bf\dfrac{d}{dx}f(x)\\ \\ \frac{\qquad\qquad}{}&\frac{\qquad\qquad}{}\\ \sf k&\sf0\\ \\ \sf sin(x)&\sf cos(x)\\ \\ \sf cos(x)&\sf-sin(x)\\ \\ \sf tan(x)&\sf{sec}^{2}(x)\\ \\ \sf cot(x)&\sf-{cosec}^{2}(x)\\ \\ \sf sec(x)&\sf sec(x)tan(x)\\ \\ \sf cosec(x)&\sf-cosec(x)cot(x)\\ \\ \sf\sqrt{x}&\sf\dfrac{1}{2\sqrt{x}}\\ \\ \sf log(x)&\sf\dfrac{1}{x}\\ \\ \sf{e}^{x}&\sf{e}^{x}\end{array}}\\ \end{gathered}[/tex]