A body of mass 2 kg is thrown up vertically with K.E. of 490 joule. If the acceleration due to gravity is 9.8 m/s2, then the height at which the K.E. of the body becomes half its original value is given by 50 m 12.5 m 25 m 10 m

Answers 1

Answer:

<br> Therefore, `(490)/(2) =2xx9. 8xxh` <br> or `h=(490)/(2 xx 2xx 9.8) or h=12.5m` <br> Thus, the required height is 12.5

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