Answer:
The correct option is (2) -1.2Δt
CFSE = −1.2Δt
Explanation:
The electronic configuration of cobalt(Co) is 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d⁷
Tetrahedral complexes when reacted with weak field ligands, the degenerate d-orbitals are split into different energies from Bary center line.
The energies are
- +0.4 Δt - dxy, dxz, dyz
- -0.6 Δt - dx² - y², dz²
Cl⁻ is a weak field ligand and hence it will give a high spin complex.
since Cl⁻ is a weak field ligand, the electrons are first filled singly and then start pairing, since the energy gap is low as compared to strong field ligands.
∴ CFSE = 4 × (−0.6)Δt + 3 × (+0.4)Δt
= −2.4Δt + 1.2Δt
= −1.2Δt
Hence the crystal field splitting energy of tetrahedral [CoCl4]2− complex is (CFSE) = −1.2Δt
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