how are the charge and current related to eAch other ​

If the length of a rod is 56 cm  when it  is bent into a rectangle then the perimeter of rectangle = 56cm a) Perimeter of rectangle = [tex]2(l+b)[/tex]

     [tex]2(l+b) = 56\\l+b = 28[/tex]

Hence, the sum of the length and breadth of the rectangle is 28cm

b) length of diagonal = 20cm

   applying pythagoras theorem;

   [tex]l^{2}+b^{2} = 20^{2} \\[/tex]

   as we know ,

   [tex](l-b)^{2} = (l+b) ^{2} -4ab[/tex]

   [tex](l-b)^{2} = (28)^{2} -4ab[/tex]                                      

   also,

    [tex](l+b)^{2} = 28^{2} \\l^{2}+ b^{2} +2ab = 784[/tex]

    [tex]400 +2ab = 784\\2ab = 384 \\ab = 192[/tex]

    [tex](l-b)^{2} = 784 - 4(192)\\(l-b)^{2} = 16[/tex]

    [tex](l-b) = 4[/tex]

    Now , solving

    [tex](l+b) = 28\\(l-b) = 4[/tex]

     we get ,

      [tex]l= 16 \\b= 12[/tex]

     So , length of rectangle = 16cm and breadth = 12cm

Answer:

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Explanation:

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Answer:

1..Atom

2..Compound

3..Mixture

4..boron, silicon and germanium.

5..Metals

Explanation:

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Answer:

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