From a disc of radius R and mass M , a circular hole of diameter R , whose rim passes through the centre is cut. What is the moment of inertia of the remaining part of the disc about a perpendicular axis, passing through the centre? a.15MR^2/32 b.13MR^2/32 c.11MR^2/32 d.9MR^2/32
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bharat in your browser the same way as you can use the search function and I have attached my cover letter for your kind of stuff and it is in the past couple of months ago in the same problem with the
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Step-by-step explanation:
A polygon with 6 side is called hexagon.
and a regular hexagon have all angle of same degree
so let the one angle of hexagon be "x"
so sum of all 6 angle =6x
and sum of all angle of any hexagon= 720°
by this
6x= 720°
x=720°/6
x=120°
let exterior angle be y
and in figure you can see that the exterior angle and interior angle are liying on a same line
so
x+y=180°
120°+y=180°
y=180°-120°
y=60°
so all exterior angle of hexagon is 60°
Mark me as branlist please.
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