The specific heat capacity of water is 4200 J/kg K. What is the change In the internal energy of 5 kg of water when it is heated from 20°G to 80°C?​

Answers 2

Mass = 5kg

Specific heat = 4200jkg

initial temperature = 20°C

Final temperature = 80°C

That is final - initial temperature =(T1 ) - (T2)

= 80 - 20 = 60

Q = mS∆T

Q = 5×4200×60 = 1,26,000kJ

Answer:

  • Change in internal energy is 1260000 KJ.

Explanation:

Topic :

  • Thermodynamics

According to the Question

It is given that,

  • Specific heat ,s = 4200 J/KgK
  • Mass of water ,m = 5kg
  • Initial temperature , Ti = 20°C
  • Final temperature ,Tf = 80°C

we have to calculate the change in internal energy .

Firstly we change the unit here

Conversion of Unit :-

→ Ti = 20+ 273 = 293 K

→ Tf = 80 + 273 = 353K

Now, calculating the change in temperature

  • ∆T = Tf - Ti

by putting the value we get

→ ∆T = 353K - 293K

→ ∆T = 60 K

From the result we conclude that "heat is absorbed by water "

Now, calculating the change in internal energy

  • Q = ms∆T

by putting the value we get

→ Q = 5 × 4200 × 60

→ Q = 4200 × 300

→ Q = 1260000 KJ

  • Hence, the change in internal energy is 1260000 KJ .

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