u=15m/s. v=0. As F=ma. a=50/20=2.5m/s^2.
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cirinopfko
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6A constant retarding force of 50N is applied to an object of mass 20 kg moving initially with a velocity of 15 mis 5 a How long does the object take to stop? b. What distance would it cover during the time?
Force = 50 N
Mass = 20 kg
Moving initially with a velocity
Time = 15 min
Initial velocity = 15 m/sec
Now , NEWTON'S SECOND LAW
F = M×a
50 = 20×a
a = 2.5 m/s²
Since ,
v = u+at
final velocity is 0
t = 15/2.5
= 6/2 sec
Now , S = ut+1/2 at²
so , 90-45
So body will stop for 6 second and travel 45 m in that time .
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bosleycsoi
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