1] A thief moves at constant speed of 15m/s a police car starts from rest as the thisf passes it. the police car accelerates at 2m/s^2 until it reaches it's maximum velocity of 20m/s. total time taken by police car when thief gets caught is.2] two particles start simultaneously from point o. one particle moves along the smooth incline and other moves freely under gravity after t=2s they reach at position A,B respectively. the distance AB is.3] a block of mass m is released on a smooth inclined wedge of inclination 45° and mass M. the height of the block (from ground) varies with time as h= 2-3t^2 ( h is in meter and t is in second) the acceleration of wedge is [g=10m/s^2][no explanation needed jst answers would work ..sorry and thank you!]

Answers 2

Answer:

1.270m

2.(v/a) cos a

3.mg / cos θ

Explanation:

Answer: 20 seconds

Explanation:

Let the thief's speed be vT.

vT = 15m/s

Let the time it takes to catch the thief be T seconds.

Then the distance covered by the police car and the thief in the time T will be the same.

We know that the police vehicle's last speed is 20m/s.

20 = 0 + 2*t

here t is the time taken to reach 20m/s.

t = 10 seconds

Distance travelled by the thief by now(10s) = 150 m

Distance travelled by the police vehicle in 10 seconds = d

2*2*d = 20^2

d = 100m

Relative speed = 20m/s - 15m/s = 5m/s

Distance to cover = 50m

Therefore time from then = 10s

It takes a total of 10+10 = 20seconds to catch the thief.