The intensity of magnetic induction at the centre of a current-carrying circular coil is B, and at a point on its axis at a dis tance equal to its radius from the centre is B,,thenB,/B, is .
Answers 1
Answer:
B
1
=
2a
μ
0
i
B
2
=
2(a
2
+a
2
)
3/2
μ
0
⋅i⋅a
2
=
2×2
2
×a
3
μ
0
ia
2
=
4
2
×a
μ
0
i
B
2
B
1
=2
2
-
Author:
kalegzba
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