the sum of three consecutive natural number is 48.find out the number by algebra method​

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Answer:

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Explanation:

The Russian Revolution of 1905, also known as the First Russian Revolution, occurred on 22 January 1905, and was a wave of mass political and social unrest that spread through vast areas of the Russian Empire. The mass unrest was directed against the Tsar alongside the nobility and ruling class.

Answer:

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Explanation:

⇒ Russia was an autocracy.

⇒ The year 1904 was a particularly bad one for Russian workers. Prices of essential goods rose so rapidly that real wages declined by 20% . 'The membership of workers' association rose dramatically.

⇒ When four members of the 'Assembly of Russian workers' which had been formed in 1904, were dismissed at the Putilov iron works, there was a call for industrial action.

⇒ Over the next few days, more than 110,000 workers in Petrograd

(now St. Petersburg) went on a strike demanding a reduction in the working day to eight hours, an increase in wages and improvement in working conditions.

⇒ When the procession of workers led by Father Gapon reached the Winter Palace, it was attacked by police and the Cossacks. Over 100 workers were killed and about 300 wounded. The incident, known commonly as 'Bloody Sunday' started a series of events that became known as the 1905 revolution.

⇒ Strikes took place all over the country and universities closed down when student bodies staged walkout, complaining about the lack of civil liberties.

⇒ Lawyers, doctors, engineers and other middle class workers established the Union Of Unions and demanded a constituent assembly.

⇒ During the 1905 revolution, the Tsar allowed the creation of an elected consultive parliament or Duma.

Step-by-step explanation:

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Answer:

ABCDE, AD=8cm,AH=6cm,AG=4cm,AF=3cm

BF=2cm,CH=3cm and EG=2.5cm

The given figure consists of 3 triangles and one trapezium.

Now

Area of △AED=

2

1

×AD×GE=

2

1

×8×2.5=10cm

2

Area of △ABF=

2

1

×AF×BF=

2

1

×3×2=3cm

2

Area of △CDH=

2

1

×HD×CH=

2

1

×(AD−AH)×3

=

2

1

×(8−6)×3=

2

1

×2×3=3cm

2

Area of trapezium BFHC=

2

1

×(BF+CH)×FH

=

2

1

×(2+3)×(AH−AF)

=

2

1

×5×(6−3)=

2

1

×5×3=7.5cm

2

Hence,

Total area of the figure = Area of △AED + Area of △ABF + Area of △CDH + Area of trapezium BFHC

=10+3+3+7.5=23.5cm

2