the area of rectangle is 6x²+xy-2y²sq.units and it's length is 2x-y unit. find its breadth​

Answers 2

Answer: Breadth is 3x+2y

Step-by-step explanation: Divide the area by the length

6x²+xy-2y²sq.units by 2x-y

Answer:

3x + 2y

Step-by-step explanation:

Area of rectangle = l × b(2x - y) × b = (6x² + xy - 2y²)b = 6x² + xy - 2y²/2x - yb = 3x + 2y

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draw a displacement vector from Visakhapatnam to hyderabad to the following diagram​
question img

Answer:

Explanation:

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answer img
(b) If PT = 6 cm, QR = 9 cm. Find the length of PQ T 6 cm Q O 9 cm R​

Answer:

⇒QR=

QP

2

+PR

2

When,

QR=QM+MR

QM=x−1

MR=x−2

QR=

6

2

+9

2

=

36+81

QR=

117

=10.82

From Question:

x−1+x−2=10.82

2x−3=10.82

x=

2

13.82

⇒QR=6.91

Step-by-step explanation:

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Answer:

Triangle Rifht angled traiangle hai kya

if a car travels 20 km south 13 km west and 14 km north in 40 minutes. find the average speed and the average velocity of the car​

Answer:

90 km is the answer hope it helpef

Answer:

The correct answer are 21.11m/s, 14420m and 8.01m/s.

Explanation:

Given:

S = 22+12+14

= 38Km

= 38000m

T = 1800s

Here,

The total distance is denoted by X.

The time is denoted by T.

The displacement is denoted by D.

The average velocity is denoted by V.

The average speed is denoted by S.

Now,

For part A,

By the equation,

\begin{gathered}S=\frac{X}{T} \\S=\frac{38000}{1800}\\S= 21.11m/s\end{gathered}

S=

T

X

S=

1800

38000

S=21.11m/s

So, the average speed is 21.11m/s.

Then,

For part B,

D = \sqrt{(22-14)^{2}+ 12^{2} }

(22−14)

2

+12

2

= 14.42Km

= 14420m

So, the sisplacement is 14420m.

Then,

For part C,

By the equation,

\begin{gathered}V=\frac{D}{T} \\V=\frac{14420}{1800}\\V= 8.01m/s\end{gathered}

V=

T

D

V=

1800

14420

V=8.01m/s

So, the average velocity is 8.01m/s.

Step-by-step explanation:

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What is the Diameter of the Planet- Neptune?​

Answer:

The diameter of the planet Neptune is 49,244km

Answer:

49,244 Kilometers

Explanation:

The Diameter of the Planet- Neptune is 49,244 Kilometers

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