(b) If PT = 6 cm, QR = 9 cm. Find the length of PQ T 6 cm Q O 9 cm R​

  • matematika

    Subject:

    Math

  • Author:

    sharon

  • Created:

    1 year ago

Answers 2

Answer:

⇒QR=

QP

2

+PR

2

When,

QR=QM+MR

QM=x−1

MR=x−2

QR=

6

2

+9

2

=

36+81

QR=

117

=10.82

From Question:

x−1+x−2=10.82

2x−3=10.82

x=

2

13.82

⇒QR=6.91

Step-by-step explanation:

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Answer:

Triangle Rifht angled traiangle hai kya

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if a car travels 20 km south 13 km west and 14 km north in 40 minutes. find the average speed and the average velocity of the car​

Answer:

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Answer:

The correct answer are 21.11m/s, 14420m and 8.01m/s.

Explanation:

Given:

S = 22+12+14

= 38Km

= 38000m

T = 1800s

Here,

The total distance is denoted by X.

The time is denoted by T.

The displacement is denoted by D.

The average velocity is denoted by V.

The average speed is denoted by S.

Now,

For part A,

By the equation,

\begin{gathered}S=\frac{X}{T} \\S=\frac{38000}{1800}\\S= 21.11m/s\end{gathered}

S=

T

X

S=

1800

38000

S=21.11m/s

So, the average speed is 21.11m/s.

Then,

For part B,

D = \sqrt{(22-14)^{2}+ 12^{2} }

(22−14)

2

+12

2

= 14.42Km

= 14420m

So, the sisplacement is 14420m.

Then,

For part C,

By the equation,

\begin{gathered}V=\frac{D}{T} \\V=\frac{14420}{1800}\\V= 8.01m/s\end{gathered}

V=

T

D

V=

1800

14420

V=8.01m/s

So, the average velocity is 8.01m/s.

Step-by-step explanation:

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