A cricket ball of 100g moving at a speed of 40 m/s is to brought to rest by a player in 0.04 sec. Find the force applied by the player​

Answers 1

Mass, m = 100g = 0.1 kg.Initial velocity, u = 30 m/s.Final velocity, v = 0.Time, t = 0.03 s.Acceleration = Change in velocity/time.Or, a = (v – u)/t.Or, a = (0 – 30)/ 0.03 = -1000 ms-2.Here, negative sign indicates retardation.Now, Force = Mass x AccelerationOr, F = (0.1) (1000) = 100 N

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