If a room 15 m long requires 7500 titles, each 15 cm × 12 cm to cover the entire floor, then the breadth of the room is :

Answer:

LCM of 15, 25, 40, and 75 is 600.

Step-by-step explanation:

The LCM of four non-zero integers, a(15), b(25), c(40), and d(75), is the smallest positive integer m(600) that is divisible by a(15), b(25), c(40), and d(75) without any remainder.

Answer:

LCM of 25,45,75 = 225

answer 225

Answer:

the language which only computer understands is binary language (0,1).

Answer:

the correct answer is 10% increase

Total sale = Price of 1 unit*Number of units sold.

The price of a cycle decreases by 20% and its demand is increased by 20%.

We are asked to find the effect on the sale of the shop.

Let the initial price be P and the initial number of cycles sold be Q.

∴ Initial sale = P*Q = PQ

In the given case, the Price is decreased by 20% and the quantity is increased by 20%.

∴ New price = P - 20% of P = P - 0.2P = 0.8P

∴ New quantity = Q + 20% of Q = Q + 0.2Q = 0.8Q

∴ New sales = 0.8P*1.2Q = 0.96PQ

∴ Change in sales = New Sales - Initial Sales = 0.96PQ - PQ = -0.04PQ

∴ Effect in sales = Change in sales/Initial sales *100%

= (-0.04PQ/PQ)*100% = -0.04*100% = -4%.

The negative sign depicts that the sales have decreased.

∴ Hence, the sales of the shop are decreased by 4%.

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The breadth of the room is 9m.

Given:

Length of the room=15 m

Dimensions of the tile=15 cm and 12 cm

Number of tiles=7,500

To find:

The room's breadth

Solution:

The required breadth can be obtained by determining the area of the floor.

The floor's area=number of tiles ×area of each tile

The area of each tile=15 cm × 12 cm

=0.15m×0.12m

=0.018 [tex]m^{2}[/tex]

Using the area of the tile,

The floor's area=7500×0.018

=7500×18/1000

=75×18/10

=75×9/5

=15×9

=135 [tex]m^{2}[/tex]

Now, the area of the floor=length of the room×breadth of the room

Using values,

135=15×breadth

135/15=breadth

9m= breadth

Therefore, the breadth of the room is 9m.