The LCM of 25, 45 and 75 is : (B) 125 (A) 450 (C) 175 (D) 225​

Answer:

We can consider the following situation in the form of an Arithmetic Progression.

a = 2.75 , d = 0.25 ( 3 - 2.75 )

AP = 2.75 , 3 , 3.25 , 3.5 ......

N = No.of terms .

[tex]S_{n} = N/2 \ ( 2a + (n-1) d ) \\\\S_{8} = 8/2 \ (2(2.5) + (8-1)0.25)\\ \\S_{8} = 4 \ ( 5 + 7(0.25) )\\\\S_{8} = 4 \ (5 + 1.75)\\\\S_{8} = 4 \ (6.75)\\\\S_{8} = 27[/tex]

________________________________________________________

Amount saved on the first day = 2.75

Ten times the amount = 27.5

So,we have to find which term of the AP has the value 27.5.

We have to find N

[tex]a_{n} = a + (n-1)d\\\\27.5 = 2.75 + 0.25(n-1)\\ \\24.75 = 0.25(n-1) \\\\99 = n-1 \\\\n = 100[/tex]

55/4, 3rd sreet

gandhi Nagar

mumbai

23 march 2022

The Secretary HSC

Divisional BOARD tope nagar

amaravati

Respected Sir,

Subject: requesting for the issue copy of HSC marksheet.

I am Amey passed HSC with 89% from science stream while shifiting our house from nashik to mumbai. In the train with my marksheet unfortunately while shifting our luggages from train i had lost my marksheet in the railway junction.

i request you to issue another copy of my hsc marksheet as soon as possible.

yoursa truly

amey

Answer:

Letter for issuance of copy of HSC marks Sheet

Explanation:

From

Anagha

To Secretary,

HSC Divisional Board Tope Nagar,

Amravati,

Date : 28- July 2022

Respected Sir,

Respectfully I am writing for a duplicate copy of my mark-sheet as I lost my Original Mark-sheet in train while traveling from Nashik to Mumbai on the train. Sir, my name is Anagha, and I was a student of HSC in science stream with 89 percent, session 2020 to 2021. Unfortunately, I beard a heavy loss due to Lose of my marksheet in train.

Now I humbly request you to please issue me a duplicate mark sheet on an urgent basis, and I will submit any required fees for a duplicate mark sheet so I will be able to continue searching for jobs.

Thanking you,

Anagha

For more idea about how to write letters like these you may visit the below link.

https://brainly.in/question/2202856

https://brainly.in/question/7995683

Answer:

the language which only computer understands is binary language (0,1).

Area of all tiles required to cover the room = 15×12×7500 = 13,50,000 cm ² = 135 m²

Area of room = 135 m²

Breadth of room = Area/Length

= 135/15

= 9

[tex] \color{red}{breadth \: of \: room \: = 9m} [/tex]

[tex]\huge\color{orange}{Thank you}[/tex]

[tex]\color{green} {Please \: mark \: me \: brainliest}[/tex]