Subject:
MathAuthor:
brodieavilaCreated:
1 year agoAnswer:
Volume of cone =
3
2
Volume of hemisphere
3
1
πr
2
h=
3
2
(
3
2
πr
3
) ; r =Common radius h = Cone height
h=
3
4
r=
3
4
(21)=28cm
Slant height, l=
r
2
+h
2
=
21
2
+28
2
=35cm
Total surface area = CSA
cone
+CSA
hemisphere
=πrl+2πr
2
=πr(l+2r)=5082cm
2
Solve any question of Surface Areas and
Author:
riggs8577
Rate an answer:
6Answer:
(a) volume of 50 toys is 16.155 m³
(b) [tex]\frac{volume \ of \ hemisphere}{volume \ of \ cone} = \frac{19386.36}{12924.24}[/tex]
Step-by-step explanation:
Given, cone: radius = 21 cm and height = 28 cm
hemisphere: radius = 21 cm
(a) [tex]volume \ of \ hemisphere = \frac{2}{3} \pi\ r^{3}[/tex]
= [tex]\frac{2}{3} (3.14)(21^{3})[/tex]
= 19386.36 cm³
[tex]volume \ of \ cone \ =\frac{1}{3} \pi\ r^{2} h[/tex]
= [tex]\frac{1}{3}(3.14)21^{2}(28)[/tex]
= 12924.24 cm³
volume of one toy = 19386.36 + 12924.24
= 32310.6 cm³ = 0.3231 m³
volume of 50 toys = 0.3231× 50 = 16.155 m³
(b) [tex]\frac{volume \ of \ hemisphere}{volume \ of \ cone} = \frac{19386.36}{12924.24}[/tex]
Author:
elsiedhvy
Rate an answer:
3