Read these numbers . write them using placement boxes and then write there expanded form .(i). 475320 (ii). 9847215 (iii). 97645310 (iv). 30458094 (A) Which is the smallest number ?(B) Which is the greatest number ?(C)Arrange these in ascending and descending order ?2. Read these no. ​

Answer:

1: Cobalt Chloride paper is used for testing for water leaks or high humidity. Moisture turns the paper light pink/white. Useful in difficult to reach places and recesses. Responsive to 50% relative humidity and above, and any direct measure of an aqueous solution.



2: It is because this paper turns into a pink colour when it reacts with water.



3: During transpiration, the leaves lose more water from their upper surface.

Answer:

The driving force behind all life cycles in the entire biosphere is the sun.

Answer:

the driving force behind all life cycle in the entire biosphere is the sun

hope it helped

ARMY FOREVER

Answer:

(i). Median Age= 58yrs

(ii). Value of x is 5.85 (approx. 6)

Step-by-step explanation:

Concept= Median and Mean of Grouped data

Given= Distribution Table and Mean

To find= Median and variable x

Explanation=

First we organize the data in our tabular form

Age Group    No. of people([tex]f_{i}[/tex])    C.F            Group Mark([tex]x_{i}[/tex])       [tex]f_{i} x_{i}[/tex]

15-25                   8                          8                           20             160

25-35                  10                         18                          30             180

35-45                  15                          33                          40            600

45-55                  25                         58                          50            1250

55-65                  40                         98                          60             2400

65-75                  24                          122                          70            1680

75-85                  18                            140                          80           1440

                         ∑[tex]f_{i}[/tex]=140                                                                   ∑[tex]f_{i} x_{i[/tex]=7710

(i). Median Age group of people enrolled in camps-

  n=140(cf) , n/2= 70

Thus this observation lies between the age group 55-65(median class).

Lower Class limit(l)= 55, Class size(h)= 10, Frequency of median class(f)= 40

Cumulative frequency of class preceding the median class is(c) 58.

Formula to find median of grouped data is Median= [tex]l+{(n/2-c)/f} * h[/tex]

equating values we get,  Median= 55+(70-58)/40  * 10= 55 +0.3*10= 55+3=58.  

Median Age= 58yrs

(ii). Find x, when x people were added in group 65-75 and Mean was 58.

If x people were  added in that group then number of people will become 24+x , Similarly the [tex]f_{i} x_{i}[/tex] value of 65-75 will become 1680+70x.

So now the new ∑[tex]f_{i} x_{i}[/tex]= 7710+70x .

Mean=∑[tex]f_{i} x_{i}[/tex]/∑[tex]f_{i}[/tex] , Equating the values we have ,

58= 7710+70x/140

=>8120=7710+70x

=>410=70x

=> x= 5.85 (approx. 6)

Therefor value of x is 5.85 (approx. 6)

Answer:

Volume of cone =

3

2

Volume of hemisphere

3

1

πr

2

h=

3

2

(

3

2

πr

3

) ; r =Common radius h = Cone height

h=

3

4

r=

3

4

(21)=28cm

Slant height, l=

r

2

+h

2

=

21

2

+28

2

=35cm

Total surface area = CSA

cone

+CSA

hemisphere

=πrl+2πr

2

=πr(l+2r)=5082cm

2

Solve any question of Surface Areas and

Answer:

(a) volume of 50 toys is 16.155 m³

(b)  [tex]\frac{volume \ of \ hemisphere}{volume \ of \ cone} = \frac{19386.36}{12924.24}[/tex]

Step-by-step explanation:

Given, cone: radius = 21 cm and height = 28 cm

hemisphere: radius = 21 cm

(a) [tex]volume \ of \ hemisphere = \frac{2}{3} \pi\ r^{3}[/tex]

             = [tex]\frac{2}{3} (3.14)(21^{3})[/tex]

             = 19386.36 cm³

  [tex]volume \ of \ cone \ =\frac{1}{3} \pi\ r^{2} h[/tex]

              = [tex]\frac{1}{3}(3.14)21^{2}(28)[/tex]

              =   12924.24 cm³

volume of one toy = 19386.36 + 12924.24

                               =  32310.6 cm³ = 0.3231 m³

volume of 50 toys = 0.3231× 50 = 16.155 m³

(b)  [tex]\frac{volume \ of \ hemisphere}{volume \ of \ cone} = \frac{19386.36}{12924.24}[/tex]