Answer:
Let d be the distance traveled by Albert.
If he travels at 20 km/h, he will reach at 2:00 pm
Time taken, t1=d20
If he travels at 15 km/h, he will reach at 12:00 noon
Time taken, t2=d15
Difference of time duration = 2 hr
d15−d20=2
d=120
t1=12020=6 and t2=12015=8
We notice that the 1 P.M is exactly midway between 12:00 noon and 2:00 pm.
Let t be the maximum time to be taken for journey,
t=t1+t22=6+82=7
Speed required =d7=1207
Ans: 17.14 km/h
Step-by-step explanation:
mark me brilliant
Author:
anthonyhxwe
Rate an answer:
2Answer: 12km/hr
Step-by-step explanation:
Let’s convert the watch into 24 hour format…
thus 2 p.m. will be 14…
assume that Sanjay started travelling at ‘x’ in the morning…
The distance to reach point A will be always constant and let’s assume it as ‘d’
thus from the first two conditions…
speed=distance/time;
10=d/(14-x) i.e. 10(14-x) = d this will be the first equation
and
15=d/(12-x) i.e. 15(12-x) = d this will be the second equation
thus by solving above equations… 10(14-x) = 15 (12-x)
we get x=8;
i.e. Sanjay started travelling at 8 a.m. in the morning…
Now let’s calculate the speed required if he want to reach A at 1 p.m. i.e. 13 in the noon according to our 24 hour format clock.
thus putting x=8 in first or second equation above,
10 (14 - 8) = d or 15 (12-8) = d
we get distance d=60 km
and the speed required to reach A at 1 p.m. will be:
speed=distance/time;
thus, speed=60/(13–8)
= 12 km/hr
with this speed Sanjay must travel to reach A at 1 p.m
Author:
danny994
Rate an answer:
4