Sanjay is travelling on his cycle and he has aimed to reach point A at 2 P.M. if he travels at 10 kmph, he will reach there at 12 noon. But if he travels at 15 kmph. At what speed must he travel to reach A at 1 P.M.?

Answers 2

Answer:

Let d be the distance traveled by Albert.

If he travels at 20 km/h, he will reach at 2:00 pm

Time taken, t1=d20

If he travels at 15 km/h, he will reach at 12:00 noon

Time taken, t2=d15

Difference of time duration = 2 hr

d15−d20=2

d=120

t1=12020=6 and t2=12015=8

We notice that the 1 P.M is exactly midway between 12:00 noon and 2:00 pm.

Let t be the maximum time to be taken for journey,

t=t1+t22=6+82=7

Speed required =d7=1207

Ans: 17.14 km/h

Step-by-step explanation:

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Answer: 12km/hr

Step-by-step explanation:

Let’s convert the watch into 24 hour format…

thus 2 p.m. will be 14…

assume that Sanjay started travelling at ‘x’ in the morning…

The distance to reach point A will be always constant and let’s assume it as ‘d’

thus from the first two conditions…

speed=distance/time;

10=d/(14-x) i.e. 10(14-x) = d this will be the first equation

and

15=d/(12-x) i.e. 15(12-x) = d this will be the second equation

thus by solving above equations… 10(14-x) = 15 (12-x)

we get x=8;

i.e. Sanjay started travelling at 8 a.m. in the morning…

Now let’s calculate the speed required if he want to reach A at 1 p.m. i.e. 13 in the noon according to our 24 hour format clock.

thus putting x=8 in first or second equation above,

10 (14 - 8) = d or 15 (12-8) = d

we get distance d=60 km

and the speed required to reach A at 1 p.m. will be:

speed=distance/time;

thus, speed=60/(13–8)

= 12 km/hr

with this speed Sanjay must travel to reach A at 1 p.m

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