factorise the following polynomial (3a-1)²-6a+2​

Answers 1

Answer:

(3a–1)²–6a+2

(3a–1)²–2(3a–1)

(3a–1) [(3a–1) –2]

(3a–1) (3a–1–2)

(3a–1) (3a–3)

(3a–1) 3(1a–1)

3(3a–1) (a–1)

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