Which term of the sequence,
⇒ 4, 7, 10, . . . . . is 37.
As we know that,
First term = a = 4.
Common difference = d = b - a = 7 - 4 = 3.
General term of an A.P.
⇒ Tₙ = a + (n - 1)d.
Using this formula in this question, we get.
⇒ 37 = 4 + (n - 1)(3).
⇒ 37 = 4 + 3n - 3.
⇒ 37 = 1 + 3n.
⇒ 37 - 1 = 3n.
⇒ 36 = 3n.
⇒ n = 12.
12 terms of the sequence 4, 7, 10, 13, . . . . . is 37.
MORE INFORMATION.Supposition of terms in an A.P.
Three terms as : a - d, a, a + d.
Four terms as : a - 3d, a - d, a + d, a + 3d.
Five terms as : a - 2d, a - d, a, a + d, a + 2d.
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