Equation to find area and perimeter of the triangle

Answer:

• A vehicle of mass 20 kg is moving with a velocity of 4 m/s .
• If it is applied on the vehicle so that the vehicle of 1 m/s after travelling a distance of 20 m.

• What is the magnitude of the force.

First, we have to find the acceleration :-

Given :

• Initial Velocity (u) = 4 m/s
• Final Velocity (v) = 1 m/s
• Distance Covered (s) = 20 m

According to the question by using the formula we get,

[tex]\implies \sf\boxed{\bold{v^2 =\: u^2 + 2as}}\\[/tex]

[tex]\implies \sf (1)^2 =\: (4)^2 + 2a \times 20\\[/tex]

[tex]\implies \sf (1 \times 1) =\: (4 \times 4) + 40a\\[/tex]

[tex]\implies \sf 1 =\: 16 + 40a\\[/tex]

[tex]\implies \sf 1 - 16 =\: 40a\\[/tex]

[tex]\implies \sf - 15 =\: 40a\\[/tex]

[tex]\implies \sf \dfrac{- 15}{40} =\: a\\[/tex]

[tex]\implies \sf - 0.375 =\: a\\[/tex]

[tex]\implies \sf\bold{a =\: - 0.375\: m/s^2}\\[/tex]

Hence, the acceleration is - 0.375 m/s² .

Now, we have to find the magnitude of the force :-

Given :

• Mass (m) = 20 kg
• Acceleration (a) = - 0.375 m/s²

According to the question by using the formula we get,

[tex]\implies \sf\boxed{\bold{Force =\: Mass \times Acceleration}}\\[/tex]

[tex]\implies \sf Force =\: 20 \times (- 0.375)\\[/tex]

[tex]\implies \sf Force =\: - 7.5\\[/tex]

[tex]\implies \sf\bold{\underline{Force =\: - 7.5\: N}}\\[/tex]

[tex]\therefore[/tex] The magnitude of the force is - 7.5 N .

Answer:

119 and 34

Step-by-step explanation:

Hope this helps you

Answer:

Aluminium is a strong and lightweight metal. This weight of aluminium is almost ⅓ rd the weight of steel. This allows the aircraft to carry more weight. The metal aluminium is corrosion resistant and this ensures the safety of passengers.

Explanation:

Answer:

Aluminium is a strong and lightweight metal. This weight of aluminium is almost 1/3 rd the weight of steel. This allows the aircraft to carry more weight. The metal aluminium is corrosion resistant and this ensures the safety of passengers.

Explanation:

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Which term of the sequence,

⇒ 4, 7, 10, . . . . . is 37.

As we know that,

First term = a = 4.

Common difference = d = b - a = 7 - 4 = 3.

General term of an A.P.

⇒ Tₙ = a + (n - 1)d.

Using this formula in this question, we get.

⇒ 37 = 4 + (n - 1)(3).

⇒ 37 = 4 + 3n - 3.

⇒ 37 = 1 + 3n.

⇒ 37 - 1 = 3n.

⇒ 36 = 3n.

⇒ n = 12.

12 terms of the sequence 4, 7, 10, 13, . . . . . is 37.

Supposition of terms in an A.P.

Three terms as : a - d, a, a + d.

Four terms as : a - 3d, a - d, a + d, a + 3d.

Five terms as : a - 2d, a - d, a, a + d, a + 2d.