Subject:
MathAuthor:
sylviabassCreated:
1 year agoAnswer:
cc the attachment or refer
Step-by-step explanation:
Hp it hlps ☺️✌️☺️Author:
jude825
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7Answer:
cos A =[tex]\frac{15}{17}[/tex]
tan A = [tex]\frac{8}{15}[/tex]
cosec A = [tex]\frac{17}{8}[/tex]
sec A = [tex]\frac{17}{15}[/tex]
cot A = [tex]\frac{15}{8}[/tex]
Step-by-step explanation:
Given sin A = [tex]\frac{8}{17}[/tex]
we know, sin A = [tex]\frac{perpendicular(P)}{hypotenuse(H)}[/tex]
using the Pythagoras theorem,
[tex]hypotenuse^{2} =base^{2} +perpendicular^{2}[/tex]
[tex]17^{2} =8^{2} +base^{2}[/tex]
[tex]base^{2} =17^{2} -8^{2} \\base^2= 289-64\\base^2=225[/tex]
we have,
base (B) = 15
Now, cos A = [tex]\frac{B}{H}[/tex] = [tex]\frac{15}{17}[/tex]
tan A = [tex]\frac{P}{B}[/tex] = [tex]\frac{8}{15}[/tex]
sec A = [tex]\frac{1}{cos A}[/tex] = [tex]\frac{17}{15}[/tex]
cosec A = [tex]\frac{1}{sin A}[/tex] = [tex]\frac{17}{8}[/tex]
cot A = [tex]\frac{1}{tan A}[/tex] = [tex]\frac{15}{8}[/tex]
learn more about trigonometric identities.
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