divide 56 in 4 parts such that the ratio of their extremes(1 and 4 term ) and product of (3 and 2 ) term is in 5:6.
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Subject:
Math -
Author:
kadewalton -
Created:
1 year ago
Answers 1
Answer:
Divide 56 in four parts in A.P. such that the ratio of the product of their extremes (1st and 4th) to the product of means (2nd and 3rd) is 5:6. Divide 56 in four parts in A.P. such that the ratio of the product of their extremes (1st and 4th) to the product of means (2nd and 3rd) is 5:6.
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