log (4y-3)=log (2y+1)-log 3

Answers 1

Answer:

y=1

Step-by-step explanation:

log (4y-3)=log (2y+1)-log 3

=> log (4y-3)=log ((2y+1)/3)

=> 4y-3 = (2y+1)/3

=> 12y - 9 = 2y + 1

=> 10y = 10

=> y=1

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