21. A train covers first 200 km of its ioey at 70 km/hr. Due to bad Weather a train covers the next 200 a km of its journey at 60 km/hr.. What will be the average speed for the first 400 km of its journey? O 78.6 km/hr O 67.6 km/hr O 76.6 km/hr O 64.6 km/hr​

Answers 2

Step-by-step explanation:

First let us find the time taken for the first 50 kms(t1)

t1 = distance/speed

t1 = 50/40

t1 = 5/4 hrs.

now let us find the time taken for the whole journey(T)

T = d/s

T = 200/60

T = 20/6

T = 10/3

now let us find the leftover time(t2)

t2 = T - t1

t2 = 10/3 - 5/4 (LCM is 12)

t2 = (40-15)/12

t2 = 25/12

now with the time and distance let us find the speed.

S = d/t

S = 150/25/12

S = 150 x 12/25( 25 x 6 =150)

S = 6 x 12

S = 72km/hr

checking

average speed = total distance/total time

Avg. Speed = 200/10/3

Avg. speed = 200 x 3/10

Avg. speed = 20 x 3

Avg. speed = 60km/hr.

Answer = 72km/hr

Concept:

Speed is determined by dividing the distance travelled by the time taken to travel it. It gives the amount of time it took to travel a certain distance divided by the distance travelled.

Speed is inversely correlated with time and directly correlated with distance.

As a result, distance equals speed x time, and time equals distance divided by speed; as speed rises, distance travelled will shorten, and vice versa

Speed = distance/ time.

Given:

train covers first 200 km of its ioey at 70 km/hr. Due to bad Weather a train covers the next 200 a km of its journey at 60 km/hr

Find:

What will be the average speed for the first 400 km of its journey?

Solution:

Since the distances are equal

we can write,

avg speed =2v₁ v₂/(v₁ +v₂)

                    =2 x70 x 60/130

                     =64.6km/hr

Therefore, the average speed =64.6km/hr  

#SPJ2

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