Write the complementary angle of 50 degree

this are some of short slogans

Answer:

1. Plant trees. Save the world.
2. Stop deforestation to save our nation.
3. Save Trees, Save The World, Save Yourself
4. Don't let our mother earth bleed for your greed!
5. Deforestation will lead to devastation.
6. “If you cut a tree, you kill a life."
7. "If you save a tree, you save a life."
8. "If you plant a tree, you plant a life.”
9. “Don’t make trees rare, keep them with care.”
10. “Take care of the trees, they will take care of you.”

Explanation:

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Answer:

यह नगर दक्कन के पठार पर मूसी नदी के किनारे स्थित है। हैदराबाद शहर की आबादी 6.9 मिलियन है, हैदराबाद मेट्रोपॉलिटन रीजन में लगभग 9.7 मिलियन के साथ, यह भारत का चौथा सबसे अधिक आबादी वाला शहर है और भारत में छठा सबसे अधिक आबादी वाला शहरी समूह है।

Answer:

Let the average after 17th innings = x

Then average after 16th innings = (x - 3)

Therefore 16 × (x - 3) + 87 = 17x

Therefore x = 39

A batsman makes a score of 87 runs in the 17th inning and thus increases his average by 3. Find his average after 17th inning.

A. 40

B. 39

C. 52

D. 55

Answer: Option B

Step-by-step explanation:

Step-by-step explanation:

AnswEr :

• To Prove :

\tan(9) = \dfrac{( \cos(36) - \sin(36) )}{( \cos(36) + \sin(36) )}tan(9)=

(cos(36)+sin(36))

(cos(36)−sin(36))

• Proof :

I'm taking LHS to Prove this Identity -

\Longrightarrow \sf \tan(9)⟹tan(9)

⠀⠀⠀⠀⋆ tan θ = sin θ / cos θ

\Longrightarrow \sf \dfrac{ \sin(9) }{ \cos(9) }⟹

cos(9)

sin(9)

⠀⠀⠀⠀⋆ we can write 9 = (45 - 36)

\Longrightarrow \sf \dfrac{ \sin(45 - 36) }{ \cos(45 - 36) }⟹

cos(45−36)

sin(45−36)

⠀⠀⠀⠀⋆ sin(A - B) = sinAcosB - cosAsinB

⠀⠀⠀⠀⋆ cos(A - B) = cosAcosB + sinAsinB

\Longrightarrow \sf \dfrac{ \sin(45) \cos(36) - \cos(45) \sin(36)}{ \cos(45) \cos(36) + \sin(45) \sin(36) }⟹

cos(45)cos(36)+sin(45)sin(36)

sin(45)cos(36)−cos(45)sin(36)

⠀⠀⠀⠀⋆ sin(45) = 1 /√2 = cos(45)

\Longrightarrow \sf \dfrac{ \dfrac{1}{ \sqrt{2} } \times \cos(36) - \dfrac{1}{ \sqrt{2} } \times \sin(36)}{ \dfrac{1}{ \sqrt{2} } \times \cos(36) + \dfrac{1}{ \sqrt{2} } \times \sin(36) }⟹

2

1

×cos(36)+

2

1

×sin(36)

2

1

×cos(36)−

2

1

×sin(36)

\Longrightarrow \sf \dfrac{ \cancel\dfrac{1}{ \sqrt{2} }( \cos(36) - \sin(36)) }{\cancel\dfrac{1}{ \sqrt{2} }( \cos(36) + \sin(36)) }⟹

2

1

(cos(36)+sin(36))

2

1

(cos(36)−sin(36))

\Longrightarrow \sf \dfrac{( \cos(36) - \sin(36)) }{( \cos(36) + \sin(36)) }⟹

(cos(36)+sin(36))

(cos(36)−sin(36))

⠀

\therefore \boxed{ \tan(9) = \dfrac{( \cos(36) - \sin(36) )}{( \cos(36) + \sin(36) )}}∴

tan(9)=

(cos(36)+sin(36))

(cos(36)−sin(36))

Answer:

To prove :

cos36° + sin36° / cos36° - sin36° = tan81°

Step-by-step explanation:

STEP 1 :

First, we consider the Left Hand Side (LHS),

STEP 2 :

Now, divide each term by cos36°, we get

STEP 3 :

By trigonometric identities, we know that   [tex]\frac{sin \alpha }{cos \alpha } = tan \alpha[/tex] , so we write

     ⇒          [tex]\frac{1 + tan 36^{0} }{1 - tan 36^{0} }[/tex]

since we rewrite the above equation as

     ⇒          [tex]\frac{1 + tan 36^{0} }{1 - 1. tan 36^{0} }[/tex]

STEP 4 :

We know that tan 45° = 1, the above equation is written as

     ⇒          [tex]\frac{tan 45^{0} + tan 36^{0} }{1 - tan 45^{0} .tan 36^{0} }[/tex]            -----> (1)

STEP 5 :

From the formula,  [tex]tan ( \alpha +\beta ) = \frac{tan \alpha + tan \beta }{1 - tan\alpha .tan \beta }[/tex]       -------> (2)

By comparing the equation (1) and (2), we write

                      α = 45° and β = 36°

STEP 6 :

Hence, tan (α + β) = tan (45° + 36°)

                             = tan 81°

                             = RHS

∴ LHS = RHS

Thus, cos36° + sin36° / cos36° - sin36° = tan81°

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