Case Study Class 9 Surface Area Volume Pls Answer

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Answers 2

Answer:

a)10.39

b)343

c)308

d)l=25

e)TSA 1870

Step-by-step explanation:

a)

length of diagonal is equal to

[tex] \sqrt{3} \: x [/tex]

x is side

so √3X6

10.39

b)

volume of cube is equal to

[tex] {s}^{3} [/tex]

=7X7X7

343

c)

CSA of hemisphere is

[tex]2\pi {r}^{2} [/tex]

=2X(22/7)X7X7

308

d)

slant hight

so r = 7 h=24 l= ?

using Pythagoras theorem

[tex] {l}^{2} = {h}^{2} + {r}^{2} [/tex]

l2=24X24+7X7

l=√625

l=25

e)

TSA of hemisphere+ TSA of cone =TSA of icecream

TSA of cone =

[tex]3\pi {r}^{2} [/tex]

so 3X22/7×7×7

=462

TSA of cone is

[tex]\pi {r}^{2} + \pi \: rl \: + \pi \: r \ (l + r)[/tex]

154+550+704

=1408

adding both we get

icecream TSA =1870

Answer:

volume of the figure if edge is 7cm is 343cm^3.

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