In the given figure, find the measures of ∆PON and ∆NPO.​

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Answers 2

Step-by-step explanation:

Sum of all angles of triangle is 180°

So, let the angle MOL be x

= 70 + 20 + x = 180

= 90 +x = 180

= x = 180 -90

= x = 90°

therefore, angle MON is equal to 90°

Now,angle MON is also equal to angle PON

hence, angle PON = 90°

Sum of all angles of triangle is 180°

So, let the angle NPO be x

= 90 + 70 + x = 180

= 160 + x = 180

= x = 180 - 160

= x= 20°

hence, angle NPO is equal to 20°

Answer:

In ΔLMO

∠L+ ∠M+ ∠O =180°

∠O+ 90° =180°

∠LON = 90°

∠PON = 90°

In ΔPON

∠P+ ∠O+ ∠N=180°

∠P+ 160=180°

∠P = 20°

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