Step-by-step explanation:
Sum of all angles of triangle is 180°
So, let the angle MOL be x
= 70 + 20 + x = 180
= 90 +x = 180
= x = 180 -90
= x = 90°
therefore, angle MON is equal to 90°
Now,angle MON is also equal to angle PON
hence, angle PON = 90°
Sum of all angles of triangle is 180°
So, let the angle NPO be x
= 90 + 70 + x = 180
= 160 + x = 180
= x = 180 - 160
= x= 20°
hence, angle NPO is equal to 20°
Author:
jerimiahn2ju
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1Answer:
In ΔLMO
∠L+ ∠M+ ∠O =180°
∠O+ 90° =180°
∠LON = 90°
∠PON = 90°
In ΔPON
∠P+ ∠O+ ∠N=180°
∠P+ 160=180°
∠P = 20°
Author:
beetlereyes
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2