if a boat takes 2 hour to travel 20 km how much time would take to travel 35 km​

Answer:

Solution. Angular S.H.M. is defined as the oscillatory motion of a body in which the torque for angular acceleration is directly proportional to the angular displacement and its direction is opposite to that of angular displacement.

Answer:

The differential equation of angular SHM is [tex]$\mathrm{I} \frac{d^{2} \theta}{d t^{2}}+c \theta=0[/tex]

Explanation:

• Angular SHM is defined as the oscillatory motion of a body in which the restoring torque responsible for angular acceleration is directly proportional to the angular displacement and its direction is opposite to that of angular displacement.

The differential equation of angular SHM is

[tex]$\mathrm{I} \frac{d^{2} \theta}{d t^{2}}+c \theta=0 \ldots(1)$$[/tex]

where[tex]$I=$[/tex] moment of inertia of the where [tex]$I=$[/tex] moment of inertia of the oscillating body,

[tex]$\frac{d^{2} \theta}{d t^{2}}=$[/tex]angular acceleration of the body when its angular displacement is [tex]$\theta$[/tex], and [tex]$c=$[/tex] torsion constant of the suspension wire,

[tex]$$\therefore \frac{d^{2} \theta}{d t^{2}}+\frac{c}{I} \theta=0$$[/tex]

Let [tex]$\frac{c}{I}=\omega^{2}$[/tex], a constant. Therefore the angular frequency, [tex]$\omega=\sqrt{\frac{c}{I}}$[/tex] and the angular acceleration,

[tex]$\mathrm{a}=\frac{d^{2} \theta}{d t^{2}}=-\omega^{2} \theta \ldots(2)$$[/tex]

The minus sign shows that the [tex]$\propto$[/tex] and [tex]$\theta$[/tex] have opposite directions. The period [tex]$T$[/tex]of angular SHM is

[tex]$\mathrm{T}=\frac{2 \pi}{\omega}=\frac{2 \pi}{\sqrt{\frac{C}{I}}}=2 \pi \sqrt{\frac{I}{C}} \ldots . .(3)$$[/tex]

This is the expression for the period terms of torque constant. Also from Eq.(2),

[tex]$$\omega=\sqrt{\left|\frac{x}{\theta}\right|}$$[/tex]

[tex]$=\sqrt{\text { angular acceleration per unit angular displacement }}$[/tex]

[tex]\begin{aligned}&\therefore \top=\frac{2 \pi}{\omega}=\frac{2 \pi}{\sqrt{\left|\frac{\alpha}{\theta}\right|}} \\&=\frac{2 \pi}{\sqrt{\text { angularacceleration per unit angulardisplacement }}}\end{aligned}[/tex]

Conditions for an Angular Oscillation to be Angular SHM

The body must experience a net Torque that is restoring in nature. If the angle of oscillation is small, this restoring torque will be directly proportional to the angular displacement.

[tex]$T \propto-\theta$[/tex]

[tex]$$\mathrm{T}=-\mathrm{k} \theta$$[/tex]

[tex]$$T=1 \alpha$$[/tex]

[tex]$$\begin{aligned}&\alpha=-\mathrm{k} \theta \\&I \frac{d^{2} \theta}{d t^{2}}=-K \theta\end{aligned}$$[/tex]

[tex]$\frac{d^{2} \theta}{d t^{2}}=-\left(\frac{K}{I}\right) \theta=-\omega_{0}^{2} \theta$$[/tex]

[tex]$\frac{d^{2} \theta}{d t^{2}}=-\omega_{0}^{2} \theta=0$$[/tex]

This is the differential equation of an angular Simple Harmonic Motion. Solution of this equation is angular position of the particle with respect to time.

[tex]$$\theta=\theta_{0} \sin \left(\omega_{0} t+\phi\right)$$[/tex]

Then angular velocity,

[tex]$$\omega=\theta_{0} \cdot \omega_{0} \cos \left(\omega_{0} t+\phi\right)$$[/tex]

[tex]$\theta_{0}$[/tex]- amplitude of the angular SHM

Learn about angular simple harmonic motion

• https://brainly.in/question/7642032?referrer=searchResults
• https://brainly.in/question/7642005?referrer=searchResults

Answer:

ekTara , khol , mandira , banshi were musical instruments

The ektara,khol,banshi,mandira were

a.popular folk musical instruments from bengal

b. Popular ragas from bengal

c. poular folk dance forms from bengal

Explanation:

Popular folk musical instruments from Bengal.

Answer:

NOT DIVISBLE

Step-by-step explanation:

1+8+6+3+7= 25 . 25 IS NOT DIVISIBLE BY 3 SO 18637 IS NOT DIVISIBLE BY THREE

Answer:

The Number Is Not Divisible By 3

Step-by-step explanation:

According To Divisibility Rules Of 3, The Sum Of Digits Of A Number Should Be Divisible By 3

1 + 8 + 6 + 3 + 7 = 9 + 6 + 10 = 15 + 10 = 25

When Try To Divide By 3 = 25/3 = 8.3 ( Recurring )

Hence Not Divisible By 3

Answer :--:

In Economics....

SAC - Short-run Average Coas.

SMC - Short-term Marginal Cost.