In a bag there are few green balls, 4 red balls and 2 yellow balls. If the probability of getting a red ball when one ball is drawn at random from the bag is 1/3 then number of green balls is equal to:

Answers 2

Answer:

green balls would be 6 as total balls are 12

Step-by-step explanation:

Probability of getting red ball P(A) = 1/3

Let the no. of green balls be, xP(A) = n(A)/ n(S

[tex] \frac{1}{3} = \frac{4}{4 + 2 + x} [/tex]

[tex] \frac{1}{3} = \frac{4}{6 + x} [/tex]

[tex]6 + x = 12[/tex]

[tex]x = 12 - 6[/tex]

[tex]x = 6[/tex]

Therefore, There are 6 green balls in the bag.

Hope it helps.

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