Given:
A drone camera is used to shoot an object P from two different positions R and S along the same vertical line QRS. The angle of depression of the object P from these two positions are 45° and 60° respectively .The distance of the object P from point Q is 50 meters ,
To Find:
Distance between R and S
Step-by-step explanation:
[tex]tan(45)=RQ\div PQ=RQ\div 50\\1=RQ\div 50\\RQ=50[/tex]
[tex]tan(60)=SQ\div PQ=(SR+RQ)\div PQ=(SR+50)\div 50\\\sqrt{3}= (SR+50)\div 50\\50\times \sqrt{3} =SR+50\\SR=50\times(\sqrt{3}-1 )\\SR=50\times 0.732=36.6\\[/tex]
- So answer to the nearest integer is 37m.
The final answer is 37m