अपने डिजाइन किए गए खिलौनों को बच्चों के लिए सुरक्षित बनाने के तरीके सुझाएँ।

a measurable extent of a particular kind, such as length, breadth, depth, or height

Answer:

a measurement of a length,width or height of something is called a dimension .

Answer:

As power=time rate of doing work in rotational motion, and work is stored in the body in the from of K. E. Using (i), P=τωα or τ=Iα, which is the required relation.

Explanation:

take bd=x

bc=50-x

take Triangle ABC AND ABD SUBSTITUTE THE VALUES YOU WILL GET THE ANS

In [tex]\triangle ABC[/tex]

In [tex]\triangle ABD[/tex]

[tex]= \frac{h}{x}[/tex]

[tex]45^\circ=\frac{h}{x}[/tex]

[tex]1=\frac{h}{x}[/tex]

In [tex]\triangle ABC[/tex]

[tex]tan \triangle 0^\circ=\frac{AB}{BC}[/tex]

[tex]\frac{1}{\sqrt{3} }=\frac{h}{50-x}[/tex]

[tex]\sqrt{3}h=50-x[/tex]

[tex]\sqrt{3}x+x=50[/tex]

[tex]DC(\sqrt{3}+1 )=50[/tex]

[tex]x=\frac{50}{\sqrt{3}+1 }\times \frac{\sqrt{3}-1 }{\sqrt{3}-1 }[/tex]

[tex]\frac{50(\sqrt{3}-1 )}{2}[/tex]

[tex]AB=18.3m[/tex]

#SPJ2

Answer:

The formula for calculating the sum of squares of the first N numbers can be described as below:

( n * ( n + 1 ) * ( 2n + 1 ) ) / 6

Where n represents the number of digits to calculate.

Explanation:

The sum of the squares of numbers is referred to as the sum of squared values of the numbers. It’s basically the addition of squared numbers.  

Here 2 terms, 3 terms, or ‘n’ number of terms, first n odd terms or even terms, set of natural numbers or consecutive numbers, etc. could be squared terms

Algorithm

The algorithm as:

Step 1: Read N.

Step 2: Let ctr = 0, sum = 0.

Step 3: Read Num.

Step 4: ctr = ctr + 1.

Step 5: Compute the square of the number i.e., = sqr (Num * Num).

Step 6: sum = sum * sqr.

Step 7: If ctr is less than N then repeat steps 3 to 6.  

Step 8: Print sum.

Step 9: End.

Program

package com.demo;

import java.util.*;

public class Main {

private static Scanner sc;

public static void main(String[] args) {

sc = new Scanner(System.in);

int n = sc.nextInt();

getvalues(n);

}

public static void getvalues(int n) {

int a = n;

int rem = 0;

int sum = 0;

while (a != 0) {

rem = a % 10;

sum = sum + (rem * rem);

a = a / 10;

}

System.out.println(sum);

}

}

def sum_of_squares_formula(end_number):

   return ( end_number * ( end_number + 1 ) * ( 2 * end_number + 1 ) ) // 6

print(sum_of_squares_formula(5))