what was the major of centre of wahabi movement is???​

i don't no this sorry bro I am sorry

xx

Answer:

1) soon

2) after

3) i don't know sorry!

exercise in grammar 2

sorry i am confused.....!!

Answer:

Adult human kidney measures 10−12cm in length, 5−7cm in width, 2−3cm in thickness with an average weight of 120−170gm.

Explanation:

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[tex] \dag \; {\underline{\boxed{\pmb{\orange{\frak{ \; Given \; :- }}}}}} [/tex]

• Principal = Rs.4000
• Rate = 7 %
• Time = 3 years

[tex] \\ \\ [/tex]

[tex] \dag \; {\underline{\boxed{\pmb{\purple{\frak{ \; To \; Find \; :- }}}}}} [/tex]

• Amount = ?

[tex] \\ \\ [/tex]

[tex] \dag \; {\underline{\boxed{\pmb{\red{\frak{ \; SolutioN \; :- }}}}}} [/tex]

[tex] \maltese [/tex] Formula Used :

• [tex] {\underline{\boxed{\pmb{\sf{ S.I = \dfrac{ P \times R \times T }{100} }}}}} [/tex]

• [tex] {\underline{\boxed{\pmb{\sf{ Amount = Principal + S.I }}}}} [/tex]

Where :

• S.I = Simple Interest
• R = Rate
• T = Time
• P = Principal

[tex] \\ \qquad{\rule{150pt}{2pt}} [/tex]

[tex] \maltese [/tex] Calculating the Simple Interest :

[tex] \begin{gathered} \longmapsto \; \; \sf { S.I = \dfrac{ P \times R \times T }{100} } \\ \end{gathered} [/tex]

[tex] \begin{gathered} \longmapsto \; \; \sf { S.I = \dfrac{ 4000 \times 7 \times 3 }{100} } \\ \end{gathered} [/tex]

[tex] \begin{gathered} \longmapsto \; \; \sf { S.I = \dfrac{ 4000 \times 21 }{100} } \\ \end{gathered} [/tex]

[tex] \begin{gathered} \longmapsto \; \; \sf { S.I = \dfrac{84000}{100} } \\ \end{gathered} [/tex]

[tex] \begin{gathered} \longmapsto \; \; \sf { S.I = \cancel\dfrac{84000}{100} } \\ \end{gathered} [/tex]

[tex] \begin{gathered} \longmapsto \; \; {\underline{\underline{\pmb{\pink{\sf{ Simple \; Interst = ₹ \; 840 }}}}}} \end{gathered} [/tex]

[tex] \\ \qquad{\rule{150pt}{2pt}} [/tex]

[tex] \maltese [/tex] Calculating the Amount :

[tex] \begin{gathered} \dashrightarrow \; \; \sf { Amount = Principal + Simple \; Interst } \\ \end{gathered} [/tex]

[tex] \begin{gathered} \dashrightarrow \; \; \sf { Amount = 4000 + 840 } \\ \end{gathered} [/tex]

[tex] \begin{gathered} \dashrightarrow \; \; {\underline{\underline{\pmb{\green{\sf{ Amount = ₹ \; 4840 }}}}}} \end{gathered} [/tex]

[tex] \\ \qquad{\rule{150pt}{2pt}} [/tex]

[tex] \maltese [/tex] Therefore :

❛❛ Rishabh had to pay ₹ 4840 to clear the debt . ❜❜

[tex] \\ {\underline{\rule{300pt}{9pt}}} [/tex]

Answer:

If M is the arithmetic mean of n observations and if a is the sum of n-4 observations, then the mean of the remaining 4 numbers is [tex]\frac{8M-a}{4}[/tex]

Step-by-step explanation:



Given

Arithmetic mean of n observations = M

That is,

the sum of n observations / n = M

So, the sum of n observations = Mn

Given

Sum of n-4 observations = a

So there mean of remaining observations = sum of n observations - the sum of n-4 observations / (n-4)

[tex]= \frac{Mn-a}{n-4}[/tex]

So the mean of remaining observations is [tex]= \frac{Mn-a}{n-4}[/tex]

Give there are 4 observations remaining

that is,

n-4 = 4

So n= 4 +4 = 8

So [tex]= \frac{Mn-a}{n-4}[/tex] = [tex]\frac{8M-a}{4}[/tex]