Answer:
Solution :-
1) a. 9a³b², 27a²b³
9a³b² = 3 × 3 × a × a × a × b× b
27a²b³ = 3 × 3 × 3 × a × a × b × b × b
∴ Common factors = 3 × 3 × a × a × b × b
= 9a²b²
b. - 8x³, 4x²y, 16xy
- 8x³ = - 2 × 2 × 2 × x × x × x
4x²y = 2 × 2 × x × x × y
16xy = 2 × 2 × 2 × 2 × x × y
∴ Common factors = 2 × 2 × x × y
= 4xy
c. 10m²n², 40m³n², 20mn
10m²n² = 2 × 5 × m × m × n × n
40m³n² = 2 × 2 × 2 × 5 × m × m × m × n × n
20mn = 2 × 2 × 5 × m × n
∴ Common factors = 2 × 5 × m × n
= 10mn
d. - 7p², 28p²t³, 14p³t³
- 7p² = - 7 × p × p
28p²t³ = 2 × 2 × 7 × p × p × t × t × t
14p³t³ = 2 × 7 × p × p × p × t × t × t
∴ Common factors = 7 × p × p
= 7p²
e. 19pqr, 95p²q²r², 57p²
19pqr = 1 × 19 × p × q × r
95p²q²r² = 5 × 19 × p × p × q × q × r × r
57p² = 3 × 19 × p × p
∴ Common factors = 19 × p
= 19p
f. 18x²yz, 6xy²z
18x²yz = 2 × 3 × 3 × x × x × y × z
6xy²z = 2 × 3 × x × y × y × z
∴ Common factors = 2 × 3 × x × y × z
= 6xyz
