bhai bata do what is a hogalala and what is the process of making it​

Grignard's reagent is an organo-magnesium halide having the general chemical formula as (R-Mg-X) which is used to form a Carbon-Carbon bond and reduce an aldehyde or ketone to alcohol.

• "R" is the organic part of the compound. "X" is a halogen, otherly known as group 17 elements like Flourine, Chlorine, etc.
• The compound helps us to create the rather difficult C-C bond or carbon-carbon bond.

• In Grignard's reaction, the desired alkyl, allyl or any carbonyl group is added to the magnesium halide which is then reacted with an aldehyde or ketone to reduce it to alcohol and add the carbonyl group to the organic compound.

The reaction of water on methyl magnesium bromide in dry ether forms methane.

CH₃-Mg-Br + H₂0  --> CH₄ (methane) + Br-Mg-OH

The lone pair electrons on the oxygen atom attack the methyl carbon and remove the MgBr part from the compound and replace it with a Hydrogen atom to form methane.

The action of Zn-HCL on ethyl iodide is that it reduces ethyl iodide to ethane.

CH₃-CH₂-I + 2[H] [tex]\frac{Zn}{HCL}[/tex]-->  CH₃-CH₃ (ethane) +  HI

Zn/HCL acts as a reducing agent thus when reacted with ethyl iodide, the nascent Hydrogen atoms attack the iodine part of the compound and replace it thus forming ethane and Hydroflouride.

Answer:

The weight of Guddy's school bag is 1 kg.

Step-by-step explanation:

please mark me brainliest

Information provided with us:

➪ The bag contain 4 books of 100 g each and 3 books of 200 g each

✰ What we have to calculate ༄

• ➪ The required total weight of bag in kg

✰So ༄

➪ The weight of 4 books of 100 g each

[tex]\implies \sf \:4 \times 100 \: g [/tex]

[tex]\implies \sf \:400 \: g [/tex]

➪ The weight of 3 books of 200 g each

[tex]\implies \sf \: 3 \times 200 \: g[/tex]

[tex]\implies \sf \:600 \: g [/tex]

✰Therefore ༄

➪Total weight of all books

[tex]\implies \sf \: 600 \: g + 400 \: g[/tex]

[tex]\implies \sf \: 1000 \: g[/tex]

✰ We know that ༄

[tex]\clubsuit \: \rm 1 \: kg \: = 1000 \: gram [/tex]

➪ So Convert 1000 gram into kg by dividing it by 1000

[tex] \rm \implies \: 1000 \div 1000[/tex]

[tex] \longrightarrow\bigstar \: \: \sf\boxed{\bold{\orange{ 1 \: kg}}}\: \: \: \bigstar\\[/tex]

✰Therefore ༄

➪ The required total weight of bag is

[tex] \longrightarrow\bigstar \: \: \sf\boxed{\bold{\pink{1\:kg }}}\: \: \: \bigstar\\[/tex]

Answer:

70 percentage in Y.



Explanation:

Percentage of accumulation is time dependent factor as time proceeds accumulation also increases.

Hence species Y arises earlier then X

Answer:

Trait Y which exists in 70% (larger fraction) of the population, is likely to have arisen earlier because in asexual reproduction, identical copies of DNA are produced and variations do not occur.

New traits come in the population due to sudden mutation and then are inherited. 70 % of the population with trait Y is likely to have been replicating that trait for a longer period than 5 % of the population with trait X.

Explanation:

MARK ME BRAINLIEST

Given:

Distance= 690 metres

Angle of elevation= 60°

Gravity (g)= 10 m/s²

To Find:

Initial velocity (V₀)

Solution:

For solving this question, we are going to use the horizontal range formula of projectile motion.

To find the maximum horizontal displacement, we consider the "y" component of the displacement equation to be zero,

⇒y= tanθ. x - [tex]\frac{g}{2u^{2}cos^{2}θ }[/tex]. x²

⇒0= tanθ. x - [tex]\frac{g}{2u^{2}cos^{2}θ }[/tex]. x²

⇒ Range =  u²sin2θ/g

[ u= Initial velocity, θ= angle of elevation]

[As all the quantities are in the S.I unit, no conversion is needed.]

Thus, now substituting the given values in the equation, we get,

⇒ 690= [u² × sin (2×45°)] / 10

⇒ 690= [u² × sin 90°] / 10

⇒ 690= u²/10                    ∵ [ sin 90°=1]

⇒ 690× 10= u²

⇒ √6900 = u

⇒ u= 83.066 m/sec

Hence, the Initial velocity (V₀) is 83.066 m/sec.