1) वृत्तांत-लेखन : • आजाद-भारत विद्यालय, कोल्हापुर में वार्षिक पुरस्कार वितरण समारोह का 70 से 80 शब्दों में वृत्तांत- लेखन कीजिए। (वृत्तांत में स्थल, काल, घटना का उल्लेख होना अनिवार्य है।) 2TOTT​

Answer:

Reject- accept

Ignore- acknowledge

Timid- Bold, forthcoming

Freedom- captivity

Explanation:

Hope it helps!

a) reject - accept, approve

b) ignore - acknowledge

c) timid - bold

d) freedom - captivity

Antonyms are words that bear meanings opposite to a specific word.

a) Reject: To dismiss something due to it being inadequate, faulty, or unacceptable.

Accept: To receive something due to it being valid, adequate, and/or without faults.

Approve: To recognize something as valid, adequate, and/or without faults.

b) Ignore: To deliberately fail to consider or take notice of something.

Acknowledge: To recognize, accept or admit the existence of something.

c) Timid: Being easily frightened and showing a lack of braveness, courage, or confidence.

Bold: Being confident and courageous and also showing a willingness to take risks.

d) Freedom: The power to be able to think, speak and act freely. Not being held captive or enslaved.

Captivity: The state of being held captive or enslaved. Not having the freedom to speak, think, and/or act freely.

Explanation:

Since international business helps a nation's economy, governments often provide benefits to attract foreign business. Such government benefits may be in the form of tax sops, subsidized resources, financial incentives, etc. International businesses also facilitate optimum utilization of resources.

Answer:

Explanation:

Given - Distance and bond length

Find - Percentage ionic character

Solution - Percentage ionic character is 76.9%.

Percentage ionic character can be calculated by the formula - observed dipole moment/theoretical dipole moment*100

Now calculating theoretical dipole moment by the formula - charge * bond length.

Bond length in centimetres = 1.6*10-⁸ centimetres

Theoretical dipole moment = 4.8*10-¹⁰*1.6*10-⁸

Theoretical dipole moment = 6.24*10-¹⁸ esu cm

Now, 10-¹⁸ esu cm is 1 Debye or 1 D

So, 6.24*10-¹⁸ esu cm will be 6.24 D.

Now, calculating percentage ionic character -

Percentage ionic character = 4.8/6.24*100

Percentage ionic character = 76.9%

Thus, percentage ionic character is 76.9%.

Given :

Dipole moment of A-B molecule = 4.8 D

Bond Length = 167 pm

To Find :

The percentage ionic character of A-B bond

Solution :

Theoretical dipole moment (μ) = Charge (q) × Distance (d)

                                                   = 1.6 × 10⁻¹⁹ × 167 × 10⁻¹²

                                                   =  267.2 × 10⁻³¹ Cm

Given, Observed Dipole moment = 4.8 D

Taking 1 D = 3.33564 × 10⁻³⁰ Cm  

So, Observed Dipole moment = 4.8 × 3.33564 × 10⁻³⁰ Cm  

Percentage ionic character = [tex]\frac{Observed Dipole Moment}{Theoretical Dipole Moment} * 100%[/tex]

                                               =  [tex]\frac{4.8 * 3.33564 * 10^-^3^0}{267.2 * 10^-^3^1} *100 %[/tex]

                                               = 60%

Therefore, the percentage ionic character of A-B bond is 60%

Hence, option (d) is correct.

Answer:

भारताचा पूर्व पश्चिम, उत्तर दक्षिण विस्तार ७,३०० आहे.

hope it is helpful to you.

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