Answer:
95.965 grams of NH3 are in 3.4×10^24 molecules of NH3
Explanation:
Taking into account the definition of avogadro's number, 95.965 grams of NH3 are in 3.4×1024 molecules of NH3.
Avogadro's Number or Avogadro's Constant is called the number of particles that make up a substance (usually atoms or molecules) and that can be found in the amount of one mole of said substance. Its value is 6.023x10²3 particles per mole. Avogadro's number applies to any substance.
Then you can apply the following rule of three: if 6.023×1023 molecules are contained in 1 mole of NH3, then 3.4×10²4 molecules are contained in how many moles of NH3?
amount of moles of NH3= (3.4×10²4 atoms x 1 mole)+ 6.023×10²³ atoms
amount of moles of NH3= 5.645 moles
Being the molar mass of NH3, that is, the amount of mass that a substance contains in one mole, 17 mode, then the mole amount of mass that 5.645 moles of the compound contain can be calculated as:
5.645 molesx 17
[tex] \frac{g}{mole} [/tex]
= 95.965 grams
Finally, 95.965 grams of NH3 are in 3.4×10^24 molecules of NH3