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Answer:

3a−5b

3a+5b

=5⇒3a+5b=5(3a−5b)

⇒3a+5b=15a−25b⇒12a=30b

⇒

ba =

1230 =

25⇒a:b=5:2

Step-by-step explanation:

Answer:

6671.74 after simplification.

Answer:

x+y=105—(1)

y+z=205—(2)

z+x=80—(3)

(1)+(2)+(3)=(x+y)+(y+z+)(z+x)=105+205+80=390

=>2(x+y+z)=390

=>x+y+z=195—(4)

(4)−(1)=(x+y+z)−(x+y)=z=195−105=90

(4)−(2)=(x+y+z)−(y+z)=x=195−205=−10

(4)−(3)=(x+y+z)−(x+z)=y=195−80=115

Answer:

Step-by-step explanation:

STEP

1

:

Equation at the end of step 1

 ((2•3a2) -  10a) -  4

STEP

2

:

STEP

3

:

Pulling out like terms

3.1     Pull out like factors :

  6a2 - 10a - 4  =   2 • (3a2 - 5a - 2)

Trying to factor by splitting the middle term

3.2     Factoring  3a2 - 5a - 2

The first term is,  3a2  its coefficient is  3 .

The middle term is,  -5a  its coefficient is  -5 .

The last term, "the constant", is  -2

Step-1 : Multiply the coefficient of the first term by the constant   3 • -2 = -6

Step-2 : Find two factors of  -6  whose sum equals the coefficient of the middle term, which is   -5 .

     -6    +    1    =    -5    That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above,  -6  and  1

                    3a2 - 6a + 1a - 2

Step-4 : Add up the first 2 terms, pulling out like factors :

                   3a • (a-2)

             Add up the last 2 terms, pulling out common factors :

                    1 • (a-2)

Step-5 : Add up the four terms of step 4 :

                   (3a+1)  •  (a-2)

            Which is the desired factorization

Final result :

 2 • (a - 2) • (3a + 1)

Answer:

STEP

1

:

Equation at the end of step 1

(((a4) + (2•3a2)) + 10a) + 42

STEP

2

:

Checking for a perfect cube

2.1 a4+6a2+10a+42 is not a perfect cube

Trying to factor by pulling out :

2.2 Factoring: a4+6a2+10a+42

Thoughtfully split the expression at hand into groups, each group having two terms :

Group 1: 10a+42

Group 2: 6a2+a4

Pull out from each group separately :

Group 1: (5a+21) • (2)

Group 2: (a2+6) • (a2)

Answer:

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